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Q.

At a given temperature, 7 gases Ne, Ar, Xe and Kr are . found to deviate from ideal gas behavior. Their equation of state is $P = \frac{RT}{(V - b)}$ which gas will exhibit steepest increase in the plot of Z vs P ?

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a

Ar

b

Ne

c

Xe

d

Kr

answer is A.

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Detailed Solution

$\begin{array}{l} P (V - b) = RT \\ PV = RT + Pb \\ \frac{PV}{RT} = \frac{RT}{RT} + \frac{Pb}{RT} \\ Z = 1 + \frac{Pb}{RT} \end{array}$
The gas having higher value of b (i.e, Xe because of maximum volume will show more sleeper slope in $Zvs \frac{1}{T})$ Slope $= \frac{b}{RT}$

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