At a given temperature, rotational kinetic energy of diatomic gas is $K_{0}$ . Find its total kinetic energy.

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$K_{T} = \frac{3}{7} K_{O}$

$K_{T} = \frac{5}{2} K_{O}$

$K_{T} = \frac{9}{2} K_{O}$

$K_{T} = \frac{3}{2} K_{O}$

answer is A.

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Detailed Solution

$\frac{f_{T}}{f_{R}} = \frac{3}{2} = \frac{K_{T}}{K_{R}} = \frac{K_{T}}{K_{O}} ∴ K_{T} = \frac{3}{2} K_{O} T o t a l k i n e t i c e n e r g y = \frac{3 k_{0}}{2} + k_{0} = \frac{5 k_{0}}{2}$

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