At a given temperature solubility product of AgCl in water is 4 ×10-10 M2. At same temperature solubility of AgCl in gm/lit is (At.wt Ag = 108 Cl = 35.5)

Ksp =S2 S=2×10-5 MS in gm / lit = S in mole/lit×GMW= 2×10-5×143.5=2.87×10-3

At a given temperature solubility product of AgCl in water is 4 ×10-10 M2. At same temperature solubility of AgCl in gm/lit is (At.wt Ag = 108 Cl = 35.5)

Ksp =S2 S=2×10-5 MS in gm / lit = S in mole/lit×GMW= 2×10-5×143.5=2.87×10-3

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At a given temperature solubility product of AgCl in water is 4 $\times$ 10^-10 M². At same temperature solubility of AgCl in gm/lit is (At.wt Ag = 108 Cl = 35.5)

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2.87 $\times 10^{- 3}$

28.7 $\times 10^{- 3}$

2 $\times$ 10^-5

28.7 $\times 10^{- 5}$

answer is D.

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Detailed Solution

$K_{sp} = S^{2} S = 2 \times 10^{- 5} M$

S in gm / lit = S in mole/lit $\times$ GMW

= $2 \times 10^{- 5} \times 143.5 = 2.87 \times 10^{- 3}$

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At a given temperature solubility product of AgCl in water is 4 ×10-10 M2. At same temperature solubility of AgCl in gm/lit is (At.wt Ag = 108 Cl = 35.5)

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At a given temperature solubility product of AgCl in water is 4 $\times$ 10^-10 M². At same temperature solubility of AgCl in gm/lit is (At.wt Ag = 108 Cl = 35.5)