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Q.

At a given temperature, total vapour pressure in Torr of a mixture of volatile components A and B is given by $P = 120 - 75 x_{B},$ hence vapour pressure of pure components A and B respectively (in Torr) are -

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a

120, 195

b

120, 75

c

120, 45

d

75, 45

answer is C.

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Detailed Solution

$P_{S} = P_{A}^{o} \cdot x_{A} + P_{B}^{o} \cdot x_{B}$

$= P_{A}^{o} (1 - x_{B}) + P_{B}^{o} \cdot x_{B}$

$P_{S} = P_{A}^{o} + x_{B} (P_{B}^{o} - P_{A}^{o}) . . . . . . (1)$

Given equation, $P_{S} = 120 - 75 x_{B} . . . . . . (2)$

On comparing eq. (1) & (2), we get

$P_{A}^{o} = 120, P_{B}^{o} - P_{A}^{o} = - 75$

$P_{B}^{o} - 120 = - 75$

$P_{B}^{o} = 45 .$

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At a given temperature, total vapour pressure in Torr of a mixture of volatile components A and B is given by P=120−75xB, hence vapour pressure of pure components A and B respectively (in Torr) are -