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At a metro station, a girl walks up a stationary escalator in time $t_{1} .$ If she remains stationary on the escalator, then the escalator take her up in time $t_{2}$ . The time taken by her to walk up on the moving escalator will be

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$t_{1} - t_{2}$

$\frac{t_{1} t_{2}}{(t_{2} + t_{1})}$

$\frac{(t_{1} + t_{2})}{2}$

$\frac{t_{1} t_{2}}{(t_{2} - t_{1})}$

answer is C.

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Detailed Solution

$t_{g} = t_{1}, t_{e} = t_{2}, t_{g e} = \frac{t_{g} t_{e}}{t_{g} + t_{e}}$
$\Rightarrow t_{ge} = \frac{t_{1} t_{2}}{t_{1} + t_{2}}$

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