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At a particular station, the TV transmission tower has a height of 100m. to triple its coverage range, height of the tower should be increased to ____

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200m

800m

600m

900m

answer is D.

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Detailed Solution

$d = \sqrt{2 Rh} \Rightarrow h \propto d^{2}$

$\frac{h_{2}}{h_{1}} = {(\frac{d_{2}}{d_{1}})}^{2} \Rightarrow \frac{h_{2}}{100} = {(\frac{3 d}{d})}^{2} \Rightarrow h_{2} = 900 m$

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