Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

At a particular temperature, the vapor pressures of two liquids A and B are respectively 120 and 180 mm of mercury. If 2moles of A and 3 moles of B are mixed to form and ideal solution, the vapor pressure of the solution at the same temperature will be (in mm of mercury

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

156

b

145

c

150

d

108

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Vapor pressure of

solution=PA+PB

PA+PB=PAoXA+PBOXB

PAoXA+PBOXB=120×25=180×35

= 48 + 108 

= 156 mm of Hg

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon