At a place the value of horizontal component of the earth's magnetic field H is $3 \times 10^{- 5} Weber / m^{2}$ . A metallic rod AB of length 2 m placed in east-west direction, having the end A towards east, falls vertically downward with a constant velocity of 50 m/s. Which end of the rod becomes positively charged and what is the value of induced potential difference between the two ends

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End A, $3 \times 10^{- 3} mV$

End A, 3 mV

End B, $3 \times 10^{- 3} mV$

End B, 3 mV

answer is B.

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Detailed Solution

Induced potential difference between two ends
$= 3 \times {10^{ - 5}} \times 2 \times 50 = 30 \times {10^{ - 3}}volt = 3\,millivolt$
By Fleming's right-hand rule, end A becomes positively charged

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