Q.

At any instant the velocity of a particle of mass 500 g is (2t  i^+3t2j^)ms1. If the force acting on the particle at t=1s is (i^+xj^)N. Then the value of x will be 

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a

2

b

6

c

3

d

4

answer is A.

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Detailed Solution

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m=0.5kg,v¯=2i^+3t2j^a¯=dvdt=2i^+6tj^F¯=ma¯=0.5=(2i^+6tj^)=i^+3t j^t=1s,F¯=i^+3j^x=3N

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At any instant the velocity of a particle of mass 500 g is (2t  i^+3t2j^)ms−1. If the force acting on the particle at t=1s is ( i^+xj^)N. Then the value of x will be