At certain temperate $K_{w}$ for water $4 \times 10^{- 14}$ which of the following is incorrect for pure water at the given temperature ?
log 2 = 0.3

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pH = 6.4 and water is acidic

pH = 6.4 and water is neutral

pOH = 6.4 and water is neutral

pH + pOH = 13.4

answer is A.

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Detailed Solution

$[H^{+}] [{OH}^{-}] = K_{w} = 4 \times 10^{- 14} In pure water [H^{+}] = [{OH}^{-}] ∴ [H^{+}] = 4 \times 10^{- 7} or P^{H} = 7 - \log 4 = 7 - 0.6 = 6.4$

pure water is neutral. $P^{OH} = 6.4$

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