At certain temperature, an ideal gas goes from stats, A (3L, 20 atm) to state B (30 L, 2 atm), reversibly. Work done during the process is

${\mathrm{W}}_{\mathrm{rev}}=-2.303 \mathrm{nRT}\log \frac{{\mathrm{V}}_{\mathrm{f}}}{{\mathrm{V}}_{\mathrm{i}}}$ 

For an ideal gas, PV = nRT

${\mathrm{W}}_{\mathrm{rev}}=-2.303 \mathrm{PV}\log \frac{{\mathrm{V}}_{\mathrm{f}}}{{\mathrm{V}}_{\mathrm{i}}}$

$$\begin{gathered} =-2.303(60\mathrm{lit}-\mathrm{atm})\log \frac{30}{3} \\ =-2.303(60\mathrm{lit}-\mathrm{atm})\log \text{ 10} \end{gathered}$$

$=(-2.303\times 60)\mathrm{lit}-\mathrm{atm}$

$=-138.18\mathrm{lit}-\mathrm{atm}$