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Q.

At constant temperature 80% AB dissociates  A2 and B2 then the equilibrium constant for 2AB(g)A2(g)+B2(g) is 

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a

1

b

0.25

c

16

d

4

answer is D.

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Detailed Solution

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2ABA2+B2 10012xxx
Given %α = 80

Kc[A2][B2][AB]2

=40×4020×20 = 4

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