At constant volume of 0.0821 litres for an ideal gas if ddT(PT)=300 at 150K. The number of moles of that gas is _____

PV=nRT; P=nRTvddT(P.T)=ddT(nRT2V); 300=2nRTVn=1

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Offline Centres

At constant volume of 0.0821 litres for an ideal gas if $\frac{d}{dT} (PT)=300$ at 150K. The number of moles of that gas is _____

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

answer is 1.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

$P V = n R T; P = \frac{n R T}{v}$

$\frac{d}{d T} (P . T) = \frac{d}{d T} (\frac{n R T^{2}}{V}); 300 = \frac{2 n R T}{V}$

$n = 1$

Watch 3-min video & get full concept clarity

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test