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Q.

At moderate pressure, the compressibility factor for a gas is given as: Z=1+0.35P− 168 T ⋅P  , where P is in bar and T is in Kelvin. What is the Boyle’s temperature of the gas?


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a

168 K

b

480 K

c

58.8 K

d

575 K 

answer is B.

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Detailed Solution

At Boyles temperature virial second coefficient = 0
Z=1+P 0.35− 168 T 0..5− 168 T =0 T= 168 0.35 =480K    
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