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Q.

At night approximately 500 photons per second must enter an unaided human eye for an object to be seen. A small light bulb emits about 5.00×1018 photons per second uniformly in all directions. The radius of the pupil of the eye is about 4×103 meters. What is the approximate maximum distance from which the bulb could be seen ?

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a

2.0×104m

b

5.0×103m

c

2.0×105m

d

20 m

answer is B.

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Detailed Solution

Photons per area per second at a distance r are 5.00×1018/4πr2. Photons per second entering the eye, radius R is then this times πR2. Set this product equal to 500 per second and solve for r. The result is [B].

5.00×10184πr2×πR2=500

5.00×10184πr2×π×16×10-6=500

r=2.0×105  m

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