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At ordinary temperatures, the molecules of an ideal gas have only translational and rotational kinetic energies. At high temperatures, they may also have vibrational energy. As a result of this, at higher temperatures. ( $C_{V}$ = molar heat capacity at constant volume).

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$C_{V} > \frac{5}{2} R$ for a diatomic gas

$C_{V} > \frac{3}{2} R$ for a monatomic gas

$C_{V} < \frac{5}{2} R$ for a diatomic gas

$C_{V} = \frac{3}{2} R$ for monatomic gas

answer is A, D.

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Detailed Solution

Vibrational KE of monatomic gas is zero at all temperatures so
$C_{V} = \frac{3}{2} R$ for monatomic gas at high temperature also in case of diatomic gas
At low temperature $C_{V} = \frac{5}{2} R$
At high temperature $C_{V} > \frac{5}{2} R$

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