At STP, 0.48g of O₂ diffused through a porous partition in 1200 seconds. The volume of CO₂ diffused under same condition is ?

$\frac{{\mathrm{n}}_{{\mathrm{O}}_2}}{{\mathrm{n}}_{{\mathrm{CO}}_2}}=\sqrt{\frac{44}{32}}\Rightarrow \frac{\frac{0.48}{32}}{{\mathrm{n}}_{{\mathrm{CO}}_2}}=\sqrt{\frac{44}{32}}$

on simplifying

${\mathrm{n}}_{{\mathrm{CO}}_2}=\frac{0.48\sqrt{\frac{32}{44}}}{32}=0.0128$

Converting moles into volume

$\mathrm{V}=\frac{\mathrm{nRT}}{\mathrm{P}}=\frac{0.0128\times 0.0821\times 273}{1}=0.286\mathrm{lit}=286\mathrm{ml}$