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At STP, 40 lit of $C O_{2}$ contains

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1.786 mole

1.934 mole

7.635 mole

5.6 mole

answer is B.

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Detailed Solution

22.4L of $C O_{2}$ at STP = 1mol
40L of $C O_{2} = \frac{40}{22.4} = 1.786$

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