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Q.

At t = 0 activity of radioactive substance is 1600 Bq and at t = 8 sec activity remains 100 Bq.  The activity at t = 2 sec is :

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a

800 Bq

b

400 Bq

c

600 Bq

d

200 Bq

answer is D.

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Detailed Solution

t=0     N0=1600Bq 

t=8s        N=100Bq

t=2s         N=?

NN0=12tT

⇒1001600=(12)8T

⇒124=128T

4=8T 

T12=T=2s

N1600=(12)22=12

N=800Bq

 

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