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At T(K) if the rate constant for a zero order reaction is $2.5 \times 10^{- 3} m s^{- 1},$ the time required for the initial concentration of reactant, R to fall from 0.10M to 0.075M at the same temperature in seconds is

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Detailed Solution

$t = \frac{[R_{0}] - {[R]}_{}}{K}$ $t = \frac{0.1 - 0.075}{2.5 \times 10^{- 3}}$

$= \frac{0.025}{2.5 \times 10^{- 3}}$ $t = 0.01 \times 10^{3} = 10 s$

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