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Q.

At T(K), the equilibrium constant for the reaction, aA(g)bB(g) is Kc. If the reaction takes place in the following form 2aA(g)2bB(g) its equilibrium constant is Kc. The correct relationship between Kc and Kc is 

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a

Kc=Kc2

b

Kc=Kc12

c

Kc=Kc1

d

Kc=Kc

answer is A.

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Detailed Solution

aA(g)bB(g), K=Kc...(1) for 2aA(g)2bB(g), multiply reaction 1 with 2, similarly Kc gets squared aA(g)bB(g)2, K=Kc2 2aA(g)2bB(g), Kc2=K'c

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