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Q.

At the height h above the surface of earth, the value of g : (R is radius of the earth)

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a

Falls to 1% of the value at the surface if h=9R

b

Falls by 1% of the value of surface if h=64 km

c

Falls by 1% of the value at the surface if h=7R

d

Falls by 1% of the value at surface if h=32 km

answer is D, A.

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Detailed Solution

When height is 9R :

gh=g(RR+h)2gh=g[R10R]2=g100

ghg=1100gh=1%  of g  at   h=9R

When height is 64 km :

gh=g[12hR]ghg=[164×26410]=98100;

Δgg=2%   ;    when height is 32 km :      gh=g[12×326400]=g×99100 

ghgg=1100Δgg=1%

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