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At two corners A and B of an equilateral triangle ABC, a south and north pole each of strength 30Am are placed. If the side of the triangle is 1m. The magnetic induction at C is

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2 × 10^–6T

8 × 10^–6 T

4 × 10^–6 T

3 × 10^–6 T

answer is A.

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Detailed Solution

$B = \frac{μ_{0}}{4 π} \frac{m}{d^{2}}$ , where d = length of each side .

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