At very high pressure, the compressibility factor of one mole of a gas is given by

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At very high pressure, the compressibility factor of one mole of a gas is given by

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$1 - p b / R T$

$1 + p b / R T$

$p b / R T$

$1 - b / V R T$

answer is A.

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Detailed Solution

The van der Waals equation of state is $(p + \frac{a}{V_{m}^{2}}) (V_{m} - b) = R T$

At high pressure, the term $a / V_{m}^{2}$ may be ignored in comparison top to get

$p (V_{m} - b) = R T$

This gives $Z = \frac{p V_{m}}{R T} = 1 + \frac{p b}{R T}$

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