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Q.

At what height above the earth’s surface does the force of gravity decrease by 10%? The radius of the earth is 6400 km? 10=3.162 

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answer is 345.6.

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Detailed Solution

g′=g−10g100=90100g

g′=gR2(R+h)2(or)910=R2(R+h)2

or  310=RR+h or

h=(10−3)R3=(10−3)×64003=345.60km

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