At what height above the ground must a mass of 5 kg be to have its PE equal in value to the KE possessed by it when it moves with a velocity of 10 m/s? (g = 10 m/s²)

Given:

• Mass (m) = 5 kg
• Velocity (v) = 10 m/s
• Acceleration due to gravity (g) = 10 m/s²

The formula for kinetic energy is:

KE = 0.5 * m * v^2

Substitute the values:

KE = 0.5 * 5 * (10)² KE = 0.5 * 5 * 100 KE = 250 J

The formula for potential energy is:

PE = m * g * h 

We need to find the height (h) where PE equals KE. So, we set PE = KE: m * g * h = 250 5 * 10 * h = 250 50h = 250 h = 250 / 50 = 5 m

Final Answer

The height above the ground is 5 meters.