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Q.

At what temperature is the kinetic energy of a gas molecule double that of its value of $127^{\circ} C$

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a

$400 K$

b

$54^{\circ} C$

c

$527^{\circ} C$

d

$800^{\circ} C$

answer is C.

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Detailed Solution

$E \propto T$ ; $\frac{E_{1}}{E_{2}} = \frac{T_{1}}{T_{2}} \Rightarrow \frac{1}{2} = \frac{400}{T_{2}} \Rightarrow T_{2} = 800 k$

T2 = 527⁰C

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