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At what temperature the following process would not be spontaneous?
$4 Fe (s) + 3 O_{2} (g) ⟶ 2 {Fe}_{2} O_{3} (s)$
$Δ H = - 1648 kJ / mole Δ S = - 560 J / mole$

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2000 K

3000 K

2900 K

2500 K

answer is B.

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Detailed Solution

$Δ H - T Δ S > 0$ (For non-spontaneous process)

$\Rightarrow T > \frac{- Δ H}{- Δ S} or T > \frac{1648 \times 10^{3}}{560} = 2943 K$

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