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Q.

At what temperature the reading on Kelvin scale is four times that on Celsius scale

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a

-68.25⁰ C

b

Not possible

c

136.5⁰ C

d

91⁰ C

answer is A.

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Detailed Solution

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$\frac{C}{100} = \frac{K - 273}{100}; K = 4 C$

$\Rightarrow C = 4 C - 273 \Rightarrow C = 91^{0} C$

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At what temperature the reading on Kelvin scale is four times that on Celsius scale