At what temperature, the volume of a given amount of gas at ${25}^{0}C$  becomes twice when pressure is kept constant?

Let the initial volume of gas be  $V_1=V.$
The final volume of gas $\left(V_2\right)$  is 2V.
$\begin{array}{l}{T}_1=273+25=298K\\ T_2=?\end{array}$
According to Charles’law
$\begin{array}{l}\frac{V_1}{T_1}=\frac{V_2}{T_2}\\ \therefore T_2=\frac{V_2\times T_1}{V_1}=\frac{2V\times 298}{V}=596K\end{array}$
Therefore, the final temperature would be 596K.