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At what temperature will the total KE of 0.30 mol of He be the same as the total KE of 0.40 mol Ar at 400 K ?

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533 K

300 K

346 K

400 K

answer is A.

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Detailed Solution

$KE = \frac{3}{2} nRT KE (He) = KE (Ar) \frac{3}{2} x 0.30 x T = \frac{3}{2} x 0.4 x 400 T = 533 K$

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