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Q.

At which of the following temperature would the molecules of a gas have twice the average kinetic energy they have at 20°C:

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a

586°C

b

80°C

c

313°C

d

40°C

answer is C.

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Detailed Solution

E∝T ∴E2E1=T2T1 ⇒2E1E1=T2(20+273) ⇒T2=293×2=586 K=313°C

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