At which of the following temperature would the molecules of a gas have twice the average kinetic energy they have at 20°C:

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40°C

80°C

313°C

586°C

answer is C.

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Detailed Solution

$E \propto T ∴ \frac{E_{2}}{E_{1}} = \frac{T_{2}}{T_{1}} \Rightarrow \frac{2 E_{1}}{E_{1}} = \frac{T_{2}}{(20 + 273)} \Rightarrow T_{2} = 293 \times 2 = 586 K = 313 ° C$

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