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Q.

At $0 ° C$ and one atm pressure, a gas occupies $100 c c .$ If the pressure is increased to one and a half-time and temperature is increased by one-third of absolute temperature, then final volume of the gas will be

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a

$66.7 c c$

b

$80 c c$

c

$100 c c$

d

$88.9 c c$

answer is B.

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Detailed Solution

$\begin{array}{l} V_{2} = \frac{P_{1} V_{1} T_{2}}{P_{2} T_{1}} \Rightarrow P_{1} = P : T_{1} = 273 K \\ P_{2} = \frac{3}{2} P : T_{2} = T_{1} + \frac{T_{1}}{3} = \frac{4}{3} \times 273 K \\ V_{2} = \frac{2 P}{3 P} \times \frac{4}{3} \times \frac{273}{273} \times 100 cc = \frac{800}{9} cc = 88.888 cc \\ = 88.9 cc \end{array}$

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