At $100°\mathrm{C}$, the $\mathrm{pH}$ of pure water is

It is given to find At $100°\mathrm{C}$, the $\mathrm{pH}$ of pure water.

$T\uparrow \Rightarrow k_{\omega }\uparrow$

$\Rightarrow \left[\underset{ }{[H^{+}}\right]\uparrow ,\left[{\mathrm{OH}}^{-}\right]$

$25°\mathrm{C}\Rightarrow {\mathrm{K}}_{\mathrm{W}}={10}^{-14}{\mathrm{M}}^{ }$

$100°\mathrm{C}\Rightarrow \left[{\mathrm{H}}^{+}\right]>{10}^{-7}mole/Lit$

${\mathrm{pH}}^H<7 \left[\mathrm{H}+\alpha <\frac{1}{{\mathrm{pH}}^H}\right.$

Hence the correct answer (C) Less than 7