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Q.

At $227 ° C$ & $4 atm, {PCl}_{5}$ is dissociated to an extent $50 %$ . At same temperature, extent of dissociation of ${PCl}_{5}$ is $0.75$ at a pressure of

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a

$2 atm$

b

$1.77 atm$

c

$8 atm$

d

$4 atm$

answer is A.

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Detailed Solution

we know, $α \propto \frac{1}{\sqrt{P}}$

$\frac{α_{1}}{α_{2}} = \sqrt{\frac{P_{2}}{P_{1}}}$

${(\frac{α_{1}}{α_{2}})}^{2} = \frac{P_{2}}{P_{1}}$

$P_{2} = \frac{0 . 5^{2} \times 4}{0 . 75^{2}} = 1.77 atm$

Therefore, the correct option is (A).

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