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Q.

At 25°C and 1 atm pressure, the enthalpy of combustion of benzene (1) and acetylene (g) are -3268 kJ mol-1 and -1300 kJ mol-1, respectively. The change in enthalpy for the reaction 3C2H2( g)C6H6(l), is

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a

+324 kJ mol-1

b

+632 kJ mol-1

c

-632 kJ mol-1

d

-732 kJ mol-1

answer is C.

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Detailed Solution

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ΔH=ΔHC(Reactant)ΔHC(Product)  

 =[3×(1300)(3268)] =632kJmol1

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