At $25^{o} C$ and 760 mm of Hg pressure, a gas occupies 600 mL. volume. What will be it's pressure at a height where temperature is $10^{o} C$ and volume of gas is 640 mL?

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767.7 mm Hg

655.5 mm Hg

565.5 mm Hg

676.6 mm Hg

answer is B.

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Detailed Solution

$P_{1} = 760 mm Hg; P_{2} = ?; V_{1} = 600 mL; V_{2} = 640 mL$

$T_{1} = (25 + 273) = 298 K, T_{2} = (10 + 273) = 283 K$

$\frac{P_{2} V_{2}}{T_{2}} = \frac{P_{1} V_{1}}{T_{1}} \Rightarrow P_{2} = \frac{760 \times 600 \times 283}{640 \times 298} = 676.6 mm Hg$

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