Q.

At 27°C a gas is compressed suddenly such that its pressure becomes (18) of original pressure. Final temperature will be (γ=53)

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a

327k

b

-142°C

c

300k

d

420k

answer is C.

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Detailed Solution

Adiabatic relation between temperature and pressure is  P1-γTγ = constant

P11-γT1γ=P21-γT2γ

Here P1=P, P2=P8  T1=300K, T2=?

Substituting we get 81-γ300γ=T2γ T2=300435131 K=-1420C

 

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