At $300 \mathrm{K}$ rate constant for $\mathrm{A}\to$products at $\mathrm{t}=50 \min$ is $0.02{ \mathrm{s}}^{-1}$, then rate constant at$\mathrm{t}=75 \min \& 310\mathrm{k}$ will be $\left(\text{ in }{\mathrm{s}}^{-1}\right.\text{ ) }$

Given that,
Rate of constant =0.02 at $300 \mathrm{K}$
Time $\mathrm{t}=50 \min$
Time ${\mathrm{t}}^{\text{'}}=75 \min$
We know that,
Every $10{}^0\mathrm{C}$ rise in temperature, the rate of reaction doubles itself.
 Calculate the rate of constant at $310 \mathrm{K}$
Using formula of rate of constant
${\mathrm{k}}_2=2{\mathrm{k}}_1$
Where, k= rate of constant
Put the value into the formula
${\mathrm{k}}_2=2\times 0.02$

The rate of constant is 0.04 .