At $5 \times 10^{5}$ bar pressure, density of diamond and graphite are 3 glee and 2 glee respectively, at certain temperature T. Find the value of $Δ U - Δ H$ for the conversion of 1 mole of graphite to 1 mole of diamond at temperature T:

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- 100 kJ/mol

100 kJ/mol

50 kJ/mol

None of these

answer is A.

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Detailed Solution

Graphite $\to$ Diamond

$\begin{array}{l} 1 mole = 12 g \\ V = 6 cc V = 4 cc \\ Δ H = Δ U + Δ (P V) \\ Δ U - Δ H = - Δ (P V) \\ = \frac{- 5 \times 10^{5} \times 100 \times 10^{3}}{1000} \times [4 - 6] \times 10^{- 6} \\ = + 100 kJ \end{array}$

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