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Q.

At $90^{0} C$ , pure water has $[H_{3} O^{+}] = 10^{- 6} mol / litre$ . The value of $K_{w}$ at $90^{0} C$ is

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a

$10^{- 12}$

b

$10^{- 14}$

c

$10^{- 8}$

d

$10^{- 6}$

answer is B.

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Detailed Solution

For pure water, $[H^{+}] = [{OH}^{-}]$

$∴ K_{w} = [H^{+}] [{OH}^{-}] = {[H^{+}]}^{2} = {(10^{- 6})}^{2} = 10^{- 12}$

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At 900C, pure water has H3O+=10-6 mol/litre. The value of Kw at 900C is