Atmospheric pressure is $1.01' 10^{5}$ pascal. How much force is exerted by air on the inside of a window plane that is 40cm'100cm

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$2.04' 10^{5} N$

$4.04' 10^{4} N$

$4.04' 10^{6} N$

$2.04' 10^{4} N$

answer is B.

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Detailed Solution

$P = 1.01 \times 10^{5} P a A = (40 \times 100) c m^{2} = 4000 c m^{2} = 4000 \times 10^{- 4} m^{2} = 0.4 m^{2} F = P \times A = 1.01 \times 10^{5} \times 0.4 = 0.404 \times 10^{5} N F = 4.04 \times 10^{4} N$

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