Atomic mass of $_{6}^{13} C$ is 13.00335 amu and its mass number is 13.0. If 1 amu = 931 MeV, binding energy of the neutrons present in the nucleus is

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0.24 MeV

1.44 MeV

3.12 MeV

1.68 MeV

answer is D.

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Detailed Solution

$\begin{array}{l} C^{13} \to C^{12} + n_{0}^{1} + Q; \\ BE (n_{0}^{1}) = Δm \times 931 \\ Δm = 13 .00335 - 13 .0 = 0 .00335 \\ ∴ BE = 0 .00335 \times 931 \approx 3 .12 Me V \end{array}$

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