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Q.

Atomic number of Iodine is 53 and its mass number is 125. Radius of iodine is approximately. (R0 = 1.2 × 10-15m)

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a

6 × 10–5m

b

6 × 10–11m

c

6 × 10–18m

d

6 × 10–15m

answer is C.

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Detailed Solution

R=RoA1/3=1.2×10−15(125)1/3R=6×10−15m

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