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Q.

Atomic number of Iodine is 53 and its mass number is 125. Radius of iodine is approximately. (R₀ = 1.2 × 10^-15m)

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a

6 × 10^–5m

b

6 × 10^–11m

c

6 × 10^–18m

d

6 × 10^–15m

answer is C.

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Detailed Solution

$\begin{array}{l} R = R_{o} A^{1 / 3} = 1 .2 \times 10^{- 15} (125)^{1 / 3} \\ R = 6 \times 10^{- 15} m \end{array}$

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