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Q.

Atomic number of the centrtal atom in MCl₂ is 50. The shape of gaseous MCl₂ is given as

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a

$\large Cl\; - \;\mathop M\limits^{ \bullet \;\; \bullet } \; - \;Cl$

b

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c

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d

$Cl\; - \;\mathop {\mathop M\limits_{ \bullet \;\; \bullet } }\limits^{ \bullet \;\; \bullet } \; - \;Cl$

answer is D.

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Detailed Solution

Z = 50 is 'Sn' belonging to 14^th group (IV A)

MCl₂

Electron pair = $\frac{1}{2} (4+2-0+0)$

= 3

$\therefore$ Hybridization of 'M' is sp²

Number of bond pairs = 2

Number of lone pairs = 3 - 2 = 1

$\therefore$ MCl₂ ... 2 bond pairs + 1 lone pair

$\therefore$ It has bent shape

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