Q.

Atomic weight of boron is 10.81 and it has two isotopes B10 5  and  B11 5 . Then ratio of B10 5 :5B11 in nature would be

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a

15 : 16

b

19 : 81

c

10 : 11

d

81 : 19

answer is A.

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Detailed Solution

Let the percentage of B10 atoms be x, then Average atomic weight
=10x+11(100-x)100=10.81x=19    NB10NB11=1981

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