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Atomic mass number of an element thorium is 232 and its atomic number is 90. The end product of this radioactive element is an isotope of
lead (atomic mass 208 and atomic number 82). The number of alpha and beta particles emitted is

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$α = 3, β = 3$

$α = 4, β = 6$

$α = 6, β = 4$

$α = 6, β = 0$

answer is B.

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Detailed Solution

$n_{α} = \frac{A - A'}{4} = \frac{232 - 208}{4} = 6 and n_{β} = (2 n_{α} - Z + Z') = (2 x 6 - 90 + 82) = 4$

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