Atoms of element B form ccp lattice and atoms of A occupy 1/3^rdof tetrahedral voids. The formula of the compound formed by the elements A and B is

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$A_{4} B_{3}$

$A_{2} B_{3}$

$A_{3} B_{2}$

$A_{3} B_{4}$

answer is A.

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Detailed Solution

The atoms of element B form the ccp structure, the number of B atoms are 6Bx1/2 + 8Bx1/8 =4B

The number of tetrahedral voids generated is twice the number of B atoms.
Thus, the number of tetrahedral voids = 8B
The atom A occupies (1/3) of these tetrahedral voids.
Hence, the number of A atom=8B×1/3=8B/3

Formula of compound= A_8/3B₄

Formula of compound= A₂B₃

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