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Average atomic weight of boron is 10.10 and boron exists in two isotopic forms $B^{10}$ and $B^{11}$ . The percentage abundance of $B^{10}$ is ____?

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10%

90%

30%

40%

answer is B.

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Detailed Solution

Assume percentage abundance of $B^{10} = x$

So percentage abundance of $B^{11} = 100 - x$

Applying formula,

$\frac{x \times 10 + (100 - x) 11}{100} = 10.10$

$\Rightarrow 10 x + 1100 - 11 x = 1010$

$x = 90$

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