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Q.

Average of n numbers is a. The first number is increased by 2, second one is increased by 4, the third one is increased by 8 and so on. The average of the new number is

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a

a+2⋅2n−1n

b

a+2⋅2n+1n

c

a+2n+1−1n

d

a+2n−1n

answer is A.

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Detailed Solution

Average =na+2+4+8+….+2nn

=na+22n−12−1n=a+2⋅2n−1n

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